3. You can define the operator << inside the namespace which myClass is defined: std::ostream& operator << (std::ostream & str, const myClass& cls) str << cls.a << " " << cls.b << std::endl; Because you've promised myClass has a friend in name-space n1 but you actually declare the operator in global name-space.. You've given a specific class within cereal (cereal::access) access to your member variables with the friend class cereal:;access, but you try to access the member variables directly in the non-member save function, which does not have access to the data.If you wanted this function to access those private members, you would need to have it explicitly listed as a friend as well.

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In function 'int main()': 11:16: error: 'double Circle::radius' is private double radius; ^ 31:9: error: within this context obj.radius = 1.5; ^ However, we can access the private data members of a class indirectly using the public member functions of the class. Below program explains how to do this:. size is a private variable in Queue, that's why your print function in Queue2 can't see it. If you want Queue2 to see size, you can put it under "protected:" instead of "private:" Protected basically means "the same as private, but child classes can see it too"